Two projectiles are shot into the air from the same location. The paths of the projectiles are parabolas and are given by (a) y = -0.0013x + x + 17 and ( b ) y =- x _x + 17 81 3 where x is the horizontal distance and y is the vertical distance, both in feet. Determine which projectile goes higher by locating the vertex of each parabola. (Round your answers to two decimal places.) (a) y = -0.0013x2+ x + 17 ( x, y) = ( 384.62, 207.31 X ( b ) y = = x + 4x + 17 81 3 ( x, y ) = 54,53 Thus, projectile (a) goes 156.31 V feet higher than the other projectile