Two simple pendulums, A and B$,$ are each $3\mathrm{.}0$ m long, and the period of pendulum A is T$.$ Pendulum A is twice as heavy as pendulum B$.$ What is the period of pendulum B$?$a$)$ Tb$)$ T $/($sqrt$(2))$c$)$ T$/2$d$)72$e$)27$