Two teams, A and B, play in a series. In each game of the series, either...

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Two teams, A and B, play in a series. In each game of the series, either Team A wins or Team B wins - there are no ties. Team A has a 60% chance of winning each game, independent of other games. The series ends and a winner is declared when one of the teams has won two more games than the other team. (a) What is the expected number of games played? (b) Given that Team B wins the first game, what is the probability that the series will last at least 8 games? (c) Given that Team B wins the first game, what is the probability that Team B wins the series? Two teams, A and B, play in a series. In each game of the series, either Team A wins or Team B wins - there are no ties. Team A has a 60% chance of winning each game, independent of other games. The series ends and a winner is declared when one of the teams has won two more games than the other team. (a) What is the expected number of games played? (b) Given that Team B wins the first game, what is the probability that the series will last at least 8 games? (c) Given that Team B wins the first game, what is the probability that Team B wins the series?

Answer rating: 100% (QA)

Solving the Probability of Series Length a Expected Number of Games Played To solve for the expected number of games we can consider different scenarios based on how many games Team A wins before Team ... View the full answer