Two tests are run during this lab, in two separate beakers. The first beaker contains 0.50 g of copper(II) chloride dihydrate and 0.08 g of aluminum. After reacting and drying the product, 0.178 g of solid copper is massed. The second beaker contains 0.53 g of copper(II) chloride dihydrate and 0.05 g of aluminum. After reacting and drying the product, 0.182 g of solid copper is massed. This data is summarized below in Table 1.

Analysis	Beaker 1	Beaker 2
Mass of CuCl22H2O(s) added (g)	0.50	0.53
Mass of Al(s) added (g)	0.08	0.05
Moles of CuCl22H2O(s) added (mol)
Moles of Al(s) added (mol)
Formula of the Limiting Reactant (if there is no limiting reactant, write N/A)
Theoretical moles of Cu(s) produced (mol)
Theoretical mass of Cu(s) produced (g)
Actual mass of Cu(s) produced (g)	0.178	0.182
Percent yield of Cu(s) (%)

Show all calculations for your BEAKER 2 ANSWERS ONLY. Be sure to use Equation Editor for your math.

Beaker 2	Calculations in EQUATION EDITOR
Moles of CuCl22H2O(s) added
Moles of Al(s) added
Formula of the Limiting Reactant (Show how you determined which reactant was limiting.)
Theoretical moles of Cu(s) produced
Theoretical mass of Cu(s) produced
Percent yield of Cu(s)

1-Write the balanced net ionic equation for the reaction in this lab using equation editor.

2-For the reaction in beaker 2, what experimental errors could have contributed to your percent yield? Explain how your error is consistent with your observations in the lab and with your results.

3-If all water was removed from beakers 1 and 2 after the reaction has gone to completion but before adding HCl and filtering, list the chemical species left in the beakers. Remember that there are no ions when all of the water has evaporated.

beaker 1-

beaker 2-

4- uppose you wanted to try a third test where there would be no limiting reactant, instead, you would have exactly the right amount of copper(II) chloride dihydrate and aluminum to fully react together with neither reactant in excess. If you use 0.723 g of CuCl2 2H2O, how much aluminum, in grams, would you need to add?

I'm confuse on some of this so please help me I'm not sure if I'm doing it right or not, thanks.