Two traverse lines AB and BC have bearing due to East N57°15’E respectively. Line AB measures 315.45. If the point of curvature is located one-third of AB from B. 

find:

a.) Radius of the Curve
b.) Chord Distance
c.) Middle Ordinate
d.) External Distance
e.) Length of Curve
f.) Stationing of PC if Point A is at 15+300.00m
g.) Stationing of PT

Answer rating: 100% (QA)

Length of curve 3154560 x 180 x AB3 525753AB Length of curve 525753 x 1000 17525 m The middle ordina... View the full answer