UDP and TCP use $1$s complement for their checksums. Suppose that you

have the following three $8-$bit bytes: $01010011,01100110,01110100.$ What is the $1$s

complement of the sum of these $8-$bit bytes? $($Note that although UDP and TCP use

$16-$bit words in computing the checksum, for this problem you are being asked to

consider $8-$bit sum.$)$ Show all work. Why is it that UDP takes the $1$s complement of

the sum: that is$,$ why not just use the sum? With the $1$s complement scheme, how

does the receiver detect errors? Is it possible that a $1-$bit error will go undetected?

How about a $2-$bit error?