Question: UDP and TCP use 1s complement for their checksums. Suppose you have the following three 8-bit bytes: 01011111, 01110000, 11001001. What is the 1s complement
UDP and TCP use 1s complement for their checksums. Suppose you have the following three 8-bit bytes: 01011111, 01110000, 11001001. What is the 1s complement of the sum of these 8-bit bytes? (Note that although UDP and TCP use 16-bit words in computing the checksum, for this problem you are being asked to consider 8-bit sums.) Show all work. Why is it that UDP takes the 1s complement of the sum; that is. Why not just use the sum? With the 1s complement schema, how does the receiver detect errors? Is it possible that a 1-bit error will go undetected? How about 2-bit error?
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