Anticipated consumer demand in a restaurant for free range steaks next month can be modeled by...
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Anticipated consumer demand in a restaurant for free range steaks next month can be modeled by a normal random variable with mean 1,300 pounds and standard deviation 90 pounds. a. What is the probability that demand will exceed 1,100 pounds? b. What is the probability that demand will be between 1,200 and 1,400 pounds? c. The probability is 0.15 that demand will be more than how many pounds? Click the icon to view the standard normal table of the cumulative distribution function. a. The probability that demand will exceed 1,100 pounds is 0.9868 (Round to four decimal places as needed.) GICOS b. The probability that demand will be between 1,200 and 1,400 pounds is 0.7330. (Round to four decimal places as needed.) c. The probability is 0.15 that demand will be more than pounds. (Round to one decimal place as needed.) Anticipated consumer demand in a restaurant for free range steaks next month can be modeled by a normal random variable with mean 1,300 pounds and standard deviation 90 pounds. a. What is the probability that demand will exceed 1,100 pounds? b. What is the probability that demand will be between 1,200 and 1,400 pounds? c. The probability is 0.15 that demand will be more than how many pounds? Click the icon to view the standard normal table of the cumulative distribution function. a. The probability that demand will exceed 1,100 pounds is 0.9868 (Round to four decimal places as needed.) GICOS b. The probability that demand will be between 1,200 and 1,400 pounds is 0.7330. (Round to four decimal places as needed.) c. The probability is 0.15 that demand will be more than pounds. (Round to one decimal place as needed.)
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Related Book For
Business research methods
ISBN: 978-1439080672
8th Edition
Authors: William G Zikmund, Barry J. Babin, Jon C. Carr, Mitch Griff
Posted Date:
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