Question: URGENT! (C Programming): An algorithm can be used to determine if a given year is a leap year or not a leap year. Based on

URGENT! (C Programming):

An algorithm can be used to determine if a given year is a leap year or not a leap year. Based on the algorithm,

A year is a leap year if it is divisible by 4 but not by 100. If a year is divisible by 4 and by 100, it is not a leap year unless it is also divisible by 400.

The date of the Easter Sunday of a given year (only from 1982 to 2048) can be determined using the following:

a is year % 19

b is year % 4

c is year % 7

d is ( 19 * a + 24 ) % 30

e is (2*b+4*c+6* d + 5 ) % 7

Using the computations, Easter Sunday falls on March ( 22 + d + e) of the given year. Note that the expression ( 22 + d + e ) makes it possible to give a date in April, so necessary adjustment must be made to get the correct date.

For each valid date input the user enters, the program should immediately display the corresponding day of the week. The program ends only when an invalid input is entered by the user.

Input: The expected date input will be in the format day month year. The accepted possible values of day will be from the range 1 to 31. The accepted possible values of month will be from the range 1 to 12. As for the possible values of year, the range is already specified. A valid date input is a correct calendar date

The output day of the week will be the correct one of the days of the week: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, or Sunday

The program should follow this input-output interface format:

Enter date: day_month_year_input Day: day_of_the_week_output

Added Difficulty: full points if your program correctly runs with the name (instead of a number, full name, not case-sensitive) of the month as the input for the month part of the input date

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