Question: URGENT CALCULUS QUESTION: FINDING ANTIDERIVATIVES AND INTEGRALS [ x-1/2 sin(2x -3/2 )dx = O A. cos(2x-3/2) + C O B. 2cos(2x -3/2) + C O

 URGENT CALCULUS QUESTION: FINDING ANTIDERIVATIVES AND INTEGRALS [ x-1/2 sin(2x -3/2

URGENT CALCULUS QUESTION: FINDING ANTIDERIVATIVES AND INTEGRALS

)dx = O A. cos(2x-3/2) + C O B. 2cos(2x -3/2) +

[ x-1/2 sin(2x -3/2 )dx = O A. cos(2x-3/2) + C O B. 2cos(2x -3/2) + C O C. cos(2x - 3/2) + C D. -3 cos(2x -3/2) + C O E. None of these. This one can't be done using the method of substitution

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