URGENT

Consider the function f(x) = 6 + v4x + 1. The goal is to compute f(x) using the definition f'(z) = lim f( Ith) - f(I) h-+0 h a) First note that _ f ( Ith) - f(I) h O VArth+I-,Art1 h O V4(Ith)+1-VAr+I h O 6+4(rth)+1-VAr+I O 6+v4rth+1-V4r+1 h b) Notice, as h -> 0, this is an indeterminate of the form . We need to multiply the expression in (a) by a factor of the form - B B so that there is no longer a division by 0 when h = 0. What is the value of B? O VArth+I+ v4x-1 O VArth+1 - VAr + 1 O V4(I +h) +1+ \\4x +I O V4(I + h) +1 - V4x -I c) If you multiply the expression in (a) by with the factor B that you have found in (b), and simplify the resulting expression, you get f(= th)-f(I) C h D where C'is a constant and D is a function of I and h. What are the values of C'and D ? Answer: [C, D] = FORMATTING: Type your answer in the form (C, D)], including the square brackets and a comma between C and D. In Mobius, VI is written sqrt(x). Use strict scientific calculator notation in your answer. The multiplication must be denoted *. For example, you must write 2x as 2*x and (r + 1)(x + 2) as (x+1)*(x+2). d) Finally, we have that f' (z) = lim f ( Ith) - f(I) h-+0 h