Use a $1$:$2$:$3$ mix design $($but this time by volume$)$ to select the weights of cement, fine

aggregate, coarse aggregate, and water to produce $50$ lbs of concrete. Using the by$-$volume

approach to produce a certain weight means you will need a bit more info. You can assume the

following: cement bulk density $=90$ b$/$ft$^3.$ fine aggregate bulk density $=100$ b$/$ft$^3.$ and

coarse aggregate bulk density $=110$ lb$/$ft$^3.$ Show your work, then summarize the final weights

below:

$$ Cement Weight:

$$ Fine Aggregate:

$$ Coarse Aggregate:

$$ Water:

If applicable, when determining the amounts by weight, the water:cement ratio is $0\mathrm{.}42$