Use a Karnaugh map to simplify the following standard SOP expression:

$x=\frac{A}{b}ar\frac{B}{b}ar(C)\frac{+}{b}ar(A)BC\frac{+}{b}ar\frac{A}{b}ar(B)C+\frac{A}{b}ar(B)C\frac{+}{b}ar(A)\frac{B}{b}ar(C)\frac{+}{b}ar\frac{A}{b}ar\frac{B}{b}ar(C)$

$x\frac{?}{b}=ar\frac{A}{b}ar\frac{B}{b}ar\frac{C}{b}ar(D)\frac{+}{b}ar\frac{A}{b}ar(B)\frac{C}{b}ar(D)\frac{+}{b}ar\frac{A}{b}ar\frac{B}{b}ar(C)D\frac{+}{b}ar\frac{A}{b}ar(B)CD\frac{+}{b}ar(A)\frac{B}{b}ar\frac{C}{b}ar(D)\frac{+}{b}ar(A)\frac{B}{b}ar(C)D+\frac{A}{b}ar(B)\frac{C}{b}ar(D)+\frac{A}{b}ar(B)CD$

$x\frac{?}{b}=ar\frac{A}{b}ar\frac{B}{b}ar\frac{C}{b}ar(D)\frac{+}{b}ar\frac{A}{b}ar\frac{B}{b}ar(C)D+A\frac{B}{b}ar\frac{C}{b}ar(D)+\frac{A}{b}ar\frac{B}{b}ar(C)D+AB\frac{C}{b}ar(D)+A\frac{B}{b}ar(C)D+\frac{A}{b}ar\frac{B}{b}ar\frac{C}{b}ar(D)+$ABCD

$x=A\frac{B}{b}ar\frac{C}{b}ar(D)+AB\frac{C}{b}ar(D)\frac{+}{b}ar\frac{A}{b}ar(B)\frac{C}{b}ar(D)\frac{+}{b}ar\frac{A}{b}ar\frac{B}{b}ar\frac{C}{b}ar(D)\frac{+}{b}ar\frac{A}{b}ar\frac{B}{b}ar(C)D+\frac{A}{b}ar\frac{B}{b}ar\frac{C}{b}ar(D)+$ABCD$+\frac{A}{b}ar(B)\frac{C}{b}ar(D)+A\frac{B}{b}ar(C)D+\frac{A}{b}ar\frac{B}{b}ar(C)D$