Use a suitable linearization to find an approximate value of sin(36) = - sin(?/5)as follows:(a) Explain why 30 = ?/6 is a good tabular

Use a suitable linearization to find an approximate value of – sin(36°) = - sin(?/5)as follows:(a) Explain why 30º = ?/6 is a good tabular point;(b) Give the equation of the tangent line at the tabular point and the value ofthe approximation;(c) Give an upper bound for the error function |E (36°)|;(d) Show that - sin(36°) ? (-0.59068, -0.59681).