Use DeMorgan's Theorem and Boolean Algebra to remove the "long bars" and put the

following expressions in a more useful form;

a$),A\frac{?}{b}=ar(F+G*H)$

b$),B\frac{?}{b}=ar(L\frac{*}{b}ar(M)\frac{*}{b}ar(K)+L\frac{+}{b}ar(K))$

c$),C\frac{?}{b}=ar((P*Q\frac{*}{b}ar(\frac{?}{\text{b}\text{a}\text{r}}(S)\frac{*}{b}ar(R)))\frac{+}{b}ar(\frac{?}{\text{b}\text{a}\text{r}}(Q)\frac{+}{b}ar(P)))$

d$)D\frac{?}{b}=ar(\frac{?}{\text{b}\text{a}\text{r}}(Z+(\frac{?}{\text{b}\text{a}\text{r}}(Y)))+(\frac{?}{\text{b}\text{a}\text{r}}(Y))*x+(\frac{?}{\text{b}\text{a}\text{r}}(W))*x)$