Use DeMorgan's theorem & Boolean algebra to simplify the following expression.

$Y\frac{?}{b}=ar(A)B\frac{+}{b}ar(\frac{?}{\text{b}\text{a}\text{r}}(A+(\frac{?}{\text{b}\text{a}\text{r}}(B))C)(\frac{?}{\text{b}\text{a}\text{r}}(A))(\frac{?}{\text{b}\text{a}\text{r}}(C))+(\frac{?}{\text{b}\text{a}\text{r}}(A))BC)$

A$.A+B+C$

B$.A+B\frac{+}{b}ar(C)$

C$.A\frac{+}{b}ar(B)+C$

D$.$ None of the above