Use Euler's method $to$ approximate the solution $to$ the given initial value problem $at$ the points $x=0\mathrm{.}1,0\mathrm{.}2,0\mathrm{.}3,0\mathrm{.}4h=0\mathrm{.}1\frac{dy}{dx}=y(8-y),y(0)=5$

The approximate solution $to\frac{dy}{dx}=y(8-y),y(0)=5,at$ the point $x=0\mathrm{.}1is$

$(Roundto$ five decimal places $as$ needed.$)$

The approximate solution $to\frac{dy}{dx}=y(8-y),y(0)=5,at$ the point $x=0\mathrm{.}2is$

$(Roundto$ five decimal places $as$ needed.$)$

The approximate solution $to\frac{dy}{dx}=y(8-y),y(0)=5,at$ the point $x=0\mathrm{.}3is$

$(Roundto$ five decimal places $as$ needed.$)$

The approximate solution $to\frac{dy}{dx}=y(8-y),y(0)=5,at$ the point $x=0\mathrm{.}4is$

$(Roundto$ five decimal places $as$ needed.$)$

The approximate solution $to\frac{dy}{dx}=y(8-y),y(0)=5,at$ the point $x=0\mathrm{.}5is$

$(Roundto$ five decimal places $as$ needed.$)$