Use Euler's method with step size $h=0\mathrm{.}1$ to approximate the solution to the initial value problem $y^{\text{'}}=x-y^2,y(1)=0,$ at the points $x=1\mathrm{.}1,1\mathrm{.}2,1\mathrm{.}3,1\mathrm{.}4,$ and $1\mathrm{.}5.$

The approximate solution to $y^{\text{'}}=x-y^2,y(1)=0,$ at the point $x=1\mathrm{.}1$ is $$

$($Round to five decimal places as needed.$)$

x$=1\mathrm{.}2,1\mathrm{.}3,1\mathrm{.}4,$ and $1\mathrm{.}5$ is also needed