Use Euler's method with step size $h=0\mathrm{.}1to$ approximate the solution $to$ the initial value problem $y^{\text{'}}=4x-y^2,y(2)=0,at$ the points $x=2\mathrm{.}1,2\mathrm{.}2,2\mathrm{.}3,2\mathrm{.}4,$ and $2\mathrm{.}5.$

The approximate solution $to{y}^{\text{'}}=4x-y^2,y(2)=0,at$ the point $x=2\mathrm{.}1is$

$(Roundto$ five decimal places $as$ needed.$)$

The approximate solution $to{y}^{\text{'}}=4x-y^2,y(2)=0,at$ the point $x=2\mathrm{.}2is$

$(Roundto$ five decimal places $as$ needed.$)$

The approximate solution $to{y}^{\text{'}}=4x-y^2,y(2)=0,at$ the point $x=2\mathrm{.}3is$

$(Roundto$ five decimal places $as$ needed.$)$

The approximate solution $to{y}^{\text{'}}=4x-y^2,y(2)=0,at$ the point $x=2\mathrm{.}4is$

$(Roundto$ five decimal places $as$ needed.$)$

The approximate solution $to{y}^{\text{'}}=4x-y^2,y(2)=0,at$ the point $x=2\mathrm{.}5is$

$(Roundto$ five decimal places $as$ needed.$)$