Use implicit differentiation to find dy$/$dx$.$

$xyxy=x^2{y}^2$

$\frac{2x{y}^{2}y1}{-2x^{2}y-x-1}$

$\frac{2x{y}^2-y-1}{-2x^{2}yx1}$

$\frac{2x{y}^2-y}{2x^{2}yx}$

$\frac{2x{y}^{2}y}{2x^{2}y-x}$