Use Iogarithmic differentiation to find $y^{\text{'}}.$

$y=\frac{\sqrt[\phantom{2}]{5-3x}(x^{2}7{)}^2}{x^{2}7x5}$

$y^{\text{'}}=\frac{\sqrt[\phantom{2}]{5-6x}(x^{2}7{)}^2}{x^{2}3x5}*(\frac{-3}{5-6x}\frac{4x}{x^{2}7}-\frac{2x3}{x^{2}3x5})$