Use Laplace transforms to solve the following initial value problem. x" - 4x = 3t; x(0) = x'(0) = 0 Click the icon to view the table of Laplace transforms. Reference x(t) = f (t ) = >-{F(s)} e(f(t)} = F(s) f (t) = e-(F(s)} L(f(t)} = F(s) (Type an expression using t as the variable.) - S (s > 0) cos kt $2 + K2 (s > 0) - 0 1 - k 2 (s > 0) sin kt S s 0) n! th S n + 1 (s > 0) cosh kt S (s > [kl) T(a + 1) ta k h+ 1 (s > 0) sinh kt (s > |KI) e at n! (s > a) s- a e atn (s-a)h+1 (s> a)