Use logarithmic differentiation to find $d\frac{y}{d}x.$

$y=\sqrt[\phantom{2}]{\frac{x^2-36}{x^{2}36}},x>6$

$\frac{dy}{dx}=\frac{76x}{\sqrt[\phantom{2}]{x^2-36}(x^{2}36{)}^{(\frac{3}{2})}}$