Question: Use M 2 5 ( A b a r = 5 0 0 m m 2 ) for beam and columns reinforcement and M 1

Use M25(Abar=500mm2) for beam and columns reinforcement and M10 for shear
reinforcement (A?bar=100mm2).
Figure 1 shows a plan view of a typical reinforced concrete floor in a 10-storey residential building. The floor system consists of a floor slab supported by 300mm wide beams. The floor supports its own weight and a superimposed dead load of 0.30kPa, in addition to a live load of
1.8kPa. The floor also supports walls by the exterior beams (B2 and B2') with a weight of 10
kNm.
It is required to:
Determine the minimum practical thickness of slabs to satisfy the deflection limits. Use one thickness for all slabs (S1, S1', S2 and S3).
Evaluate the dead, live and ultimate factored loads applying to the slabs (in kNm2)
Determine the factored bending moment and shear force developed in slabs S1-S2-S1' and slab S3
(Note S3 can be modeled as a 2m cantilever fixed to the adjacent beam B3).
Calculate the reinforcement required for slabs S1-S2-S1' to resist the maximum positive and negative moment and sketch the reinforcement in each case.
Calculate the reinforcement for slab S3 to resist the bending moment.
Assume the height for beams B1 and B2 to prevent excessive deflections, then evaluate the ultimate loads going to beam B1 and beam B2.
Note beam B1 carries its own weight, slab weight super imposed dead and live load, while B2 carries same types of load in addition to wall weight.
Determine the factored axial load transferred to columns C1 and C2 assume the columns supports 10 similar floors to that shown in Figure 1.
Design the columns C1 ad C2 to resist the factored axial forces and sketch the reinforcement .
Note C1 is a circular column and C2 is a rectangular column with a width of 300mm.
Use M 2 5 ( A b a r = 5 0 0 m m 2 ) for beam and

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