Question: Use Matlab for all questions, include graphs and comment what you did and address all questions. Upload your m-files with your submission. In this portion

Use Matlab for all questions, include graphs and comment what you did and address all questions. Upload your m-files with your submission. In this portion of the homework you will reproduce the minimalistic cell cycle model of Goldbeter, published in PNAS in 1992, a publication posted under the Resources folder Plot M dependent on C. This is called a phase plot revealing a limit cycle (see also Fig. 4 in the paper). Produce a second plot to demonstrate how a more dramatic perturbation of the initial conditions of M or C causes the system to not get back to cycle. This is a demonstration for the limit of robustness of the system. Please help!!! Thank you in advance :))

Use Matlab for all questions, include graphs and comment what you didand address all questions. Upload your m-files with your submission. In thisportion of the homework you will reproduce the minimalistic cell cycle model

Use Matlab for all questions, include graphs and comment what you did and address all questions. Upload your m-files with your submission. In this portion of the homework you will reproduce the minimalistic cell cycle model of Goldbeter, published in PNAS in 1992, a publication posted under the "Resources" folder. 3) Plot M dependent on C. This is called a phase plot revealing a limit cycle (see also Fig. 4 in the paper). Produce a second plot to demonstrate how a more dramatic perturbation of the initial conditions of M or C causes the system to not get back to cycle. This is a demonstration for the limit of robustness of the system. Here is the Berkeley Madonna code (uses multiple aux variables): DT=1e4 STOPTIME =100 d/dt(C)= Synthesis - Degradation INIT C =0.01 Synthesis =0.025 Degradation =vdX(C/(Kd+C))kddC d/dt(M)= Phosphatase 1 Kinase 1 INIT M=0.01 Phosphatase1 =VM1(C/(KC+C))((1M)/(K1+(1M))) Kinase 1=V2(M/(K2+M)) d/dt(X)= Phosphatase 2 - Kinase 2 INIT X=0.01 Phosphatase2 =MVM3((1X)/(K3+(1X))) Kinase 2=V4(X/(K4+X)) K1=0.005 K2=0.005 K3=0.005 K4=0.005 Kc=0.5 Kd=0.02 kdd=0.01 V2=1.5 V4 =0.5 vd=0.25 VM1 =3 VM3 =1 (Remark: DT=h)

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