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In the thermos shown, the innermost compartment is separated from the middle container by a vacuum. There is a final shell around the thermos. This final shell is separated from the midldle layer by a thin layer of air. The outside of the final shell comes in contact with room air. Heat transfer from the inner compartment to the next layer qi is by radiation only (since the space is evacuated). Heat transfer between the middle layer and outside shell z is by convection in a small space. Heat transfer from the outside shell to the air qs is by natural convection. The heat flux from each region of the thermos must be equal, which means q g-Find the temperatures T1 and T2 at steady state if To 250 C and qi = 10-9[(T0 + 273)4-(Ti + 273)"] 92 4(T - T2) 93 = 1.3(T2-T3); Hint: Thore are two unknown (71 and T2), so we need two equations to find thom. Theso equations are the ones given in the problem statement to ensure a stoady state heat transfer process 192 72 -93 Answer:T,-59C T2-43.3C