Use Newton's method $to$ find solutions accurate $to$ within ${10}^{-5}$ for the following problems.

$a.e^x+2^{-x}+2cosx-6=0$ for $1x2$

$b.,ln(x-1)+cos(x-1)=0$ for $1\mathrm{.}3x2$

$c.2xcos2x-(x-2{)}^2=0$ for $2x3$ and $3x4$

$d.,(x-2{)}^2-lnx=0,$ for $1x2$ and $ex4$

$e.e^x-3x^2=0$ for $0x1$ and $3x5$

$f.sinx-e^{-x}=0$ for $0x1,3x4$ and $6x7$

Repeat Exercise $5$ using the Secant method.

Repeat Exercise $6$ using the Secant method.