Use Newton's method to approximate $\sqrt[\phantom{2}]{3}.$ Let $f(x)=x^2-3,$ let $x_0=2,$ and calculate $x_1,x_2,x_3,x_4,$ and $x_5.($Since $f(x)=x^2-3$ has a zero at $2,$ use the initial value $x_0=2$ as a reasonable choice to approximate $2.)$