Use Newton's Method to approximate the zero$($s$)$ of the function. Co compare the results. $($Round your answers to four decimal places.$)$

$f(x)=-x^3+2\mathrm{.}3x^2+3\mathrm{.}48x-2\mathrm{.}382$

Newton's method:

$(smallest$ value$)x=$

$,x=$

$(largest$ value$)x=$

$(smallest$ value$)x=$

$,x=$

$(largest$ value$)x=$

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Graphing utility: $,(smallest$ value$),x=$

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