Use Newton's method with the specified initial approximation x to find x3, the third approximation to...

 

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Use Newton's method with the specified initial approximation x to find x3, the third approximation to the root of the given equation. (Round your answer to four decimal places). x3 + 2x 10, x = 1 X3 Use Newton's method with the specified initial approximation x to find x3, the third approximation to the root of the given equation. (Round your answer to four decimal places). x3 + 2x 10, x = 1 X3