use part c to answer d it is squarely x squared -1

=X-1

c. Algebraically determine the coordinates of any invariant points between the two functions. (2 marks) Points which remain invariant under certain transformations x2 - 1 = X-1 2 - 1 = ( x2 - 1 ) = = X 4-2x2+1 4 - 3 x 2 + 2= 0 x 2) 2 - 2x2 -*2+2=0 x 2 - 2 ) ( x 2 - 1 ) = 0 * 2 - 2= 0 - X= +12 x 2 - 1 = 0 - X = INT the four points x=tl and x= = are invariant under the transformation of square d. Not all points of intersection are invariant points. Explain how to be certain these are invariant points and not simply points of intersection of the graphs. Video Hint: https://vvs.wistia.com/medias/hahsbimrsg (1 mark)