$($Use printf function to display$)$ Define a signed integer a $=0$xA$53$C$0$E$60$ and an unsigned integer b $=0$xA$53$C$0$E$60.$

a$.$ Print both a and b in decimal format.

b$.$ Shift both a and b right by $4$ bits and print the outputs in hex and decimal format.

Divide both a and b by $16$ and print the answers in hexadecimal and decimal formats. Manually check if the results of shift right and that of division match for both a and b and if the results are correct.

c$.$ Repeat the steps in part b with signed integer p $=0$xA$53$C$0$E$62$ and unsigned integer q $=0$xA$53$C$0$E$62.$ Check if results match in both cases. Are the results correct $?$

d$.$ Define a signed integer x $=0$x$053$C$0$E$60$ and an unsigned integer y $=0$x$053$C$0$E$60.$

Shift x and y left by $4$ bits and print the outputs in hexadecimal and decimal format. Multiply x and y by $16$ and print the answers in hexadecimal and decimal. Manually check if for each case, the results of shift left and that of multiplication match for both a and b and if the results are correct.

d$.$ Try the same steps as in $$d$$ with signed integer x $=0$x$0$A$3$C$0$E$60$ and unsigned integer y $=0$x$0$A$3$C$0$E$60.$ Manually check if the results of multiplication and left shift match. Are the results correct $?$

More information $-$

Int is signed by default. Hence

int a; $//$ Declares a as a signed integer

unsigned int b; $//$ Declares b as an unsigned int

For printing $-$ in radix $10-$

Signed integers are printed with $\%$d$,$ unsigned integers are printed with $\%$u$.$

In radix $16,$ it stays the same $\%$x$,$ since the representation stays the same, it$$s interpretation changes.