USE PYTHON3; DO NOT IMPORT ANY PACKAGES

Create a function that processes the input dictionary according to the following rules. The input dictionary will only have non-negative integers for the keys and values.

For each key in the dictionary:

1. If the key is odd, remove this key-value pair from the dictionary

2. Else if the square of this key exists in the dictionary (as a key), square the current key's corresponding value. Do not modify the key itself.

3. Else if the square root of this key exists in the dictionary (as a key), square root the current key's corresponding value and convert it to int (with int()). Do not modify the key itself.

4. Otherwise, don't modify this key and its corresponding value.

Note: Be careful with modifying the existing dictionary while looping through it. You may want to create a new dictionary instead.

Example:

{1: 1, 2: 2, 3: 3, 4: 4, 5: 5, 6: 6} -> {2: 4, 4: 2, 6: 6}

Explanation:

Input	Reason	Output
1: 1	odd key, remove
2: 2	square of 2 (= 4) exists as a key, square the value	2: 4
3: 3	odd key, remove
4: 4	square root of 4 (= 2) exists as a key, square root the value and convert to int	4: 2
5: 5	odd key, remove
6: 6	square or square root of 6 do not exist as a key, make no change	6: 6

You can use one line dictionary comprehension if you choose

def process_dict(data):

"""

>>> process_dict({1: 1, 2: 2, 3: 3, 4: 4})

{2: 4, 4: 2}

>>> process_dict({})

{}

>>> process_dict({10: 10, 100: 100, 4: 1})

{10: 100, 100: 10, 4: 1}

"""

# YOUR CODE GOES HERE #