$($Use the $68-95-99\mathrm{.}7$ Rule to solve the problem$)$

The finishing times of a local $5k(3\mathrm{.}1$mile $)$ road race follows a normally distribution with a mean of $25$ minutes and a standard deviatiof of $3$ minutes. $N(25,3)$

What percent of finishers are expected to finish between $19$ and $31$ minutes?

Enter the value as a percent with one decimal point and no percent sign $($e$.$g$.20\mathrm{.}1)$