Use the compound interest formula, $A(t)=P(1+\frac{r}{n}{)}^{nt}$

After a certain number of years, the value of an investment account is represented by the equation $A(t)=18,750(1+\frac{0\mathrm{.}0425}{6}{)}^{90}.$

What is the value of the account $A(t)($round to the nearest cent$)?$

What was the initial deposit $P$ made to the account?

How many years $t$ has the account been accumulating interest?

What was the interest rate $r($state as a percent$)?$

$A(t)=$$$35,090\mathrm{.}60$;$P=$$$18,750$;$t=15$ years; $r=0\mathrm{.}0425\%$

$A(t)=$$$35,190\mathrm{.}60$;$P=$$$18,750$;$t=15$ years; $r=0\mathrm{.}00425\%$

$A(t)=$$$35,390\mathrm{.}61$;$P=$$$18,750$;$t=15$ years; $r=4\mathrm{.}25\%$

$A(t)=$$$35,290\mathrm{.}61$;$P=$$$18,750$;$t=15$ years; $r=0\mathrm{.}425\%$