Use the equation h equals one half gt squared plus v 0 t plus h 0h=12gt2+v0t+h0

to solve the problem, where g = 32 ft/sec2.

A horseshoe is thrown upward from an initial height of 100

feet with an initial velocity of 80 feet per second. How long after the horseshoe is projected upward

a) will it be 20 feet from the ground?

b) will it strike the ground?

After nothing

seconds, the horseshoe will be 20

feet off the ground.

(Round to two decimal places as needed.)