Use the following data to answer the question: \( \mathrm{K}_{a} \) of \( \mathrm{HF} \) is \( 6.8 \times 10^{-4}, \mathrm{~K}_{\mathrm{b}} \) of aniline is \( 4.3 \times 10^{-10}, \mathrm{~K}_{\mathrm{b}} \) of ethylamine is \( 6.41 \times 10^{-4} \) (A) \( 0.1 \mathrm{M} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{Cl}<0.1 \mathrm{M} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{Br}<0.1 \mathrm{M} \mathrm{NaCl}<0.1 \mathrm{M} \mathrm{NaF} \) (B) \( 0.1 \mathrm{M} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{Cl}<0.1 \mathrm{M} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{Br}<0.1 \mathrm{M} \mathrm{NaF}<0.1 \mathrm{M} \mathrm{NaCl} \) (C) \( 0.1 \mathrm{M} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{Br}<0.1 \mathrm{M} \mathrm{C}{ }_{2} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{Cl}<0.1 \mathrm{M} \mathrm{NaCl}<0.1 \mathrm{M} \mathrm{NaF} \) (D) \( 0.1 \mathrm{M} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{Br}<0.1 \mathrm{M} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{Cl}<0.1 \mathrm{M} \mathrm{NaF}<0.1 \mathrm{M} \mathrm{NaCl} \)