Question: Use the following information to answer the next question Current Carrying Coiled of Wire O A chlorine ion projected perpendicularly into the plane of paper.

 Use the following information to answer the next question Current Carrying

Use the following information to answer the next question Current Carrying Coiled of Wire O A chlorine ion projected perpendicularly into the plane of paper. A chlorine ion (CI) with a mass of 5.85 . 10 kg is projected with an energy of 8.50 kev perpendicularly into a magnetic field with a strength of 0.650 T. 18. Based on the above information, the kinetic energy of the chlorine ion, in joules, is: 1.36 x 10-15 J 8.50 x 103 J 17. Select the direction of the magnetic field that is placed at positions a, b and c. Choose: 1.36 x 10-18 J 1 - right 8.50 J 2 - up 3- left 4 - down 19. Based on the above information, the magnetic fo in on the chlorine ion will be towards: Position b (in first box) the left Position a (in second box) the right Position c (in third box) the bottom of the page the top of the page Your answer: OOOO 16. A small conducting sphere, with a charge of 4.25 nC, moves from a position in an electric field with an electrical potential of 15.0 V to a position with an electrical potential of 40.0 V. The energy gained by the sphere is: 1.06 x 10" J of kinetic energy 20. An alpha particle, entering a uniform external magnetic field of 1.75 T, begins to move in a circular path of radius 0.0720 m. The magnitude of the electric field 1.06 x 10"/J of electric potential energy required to allow the alpha particle to pass straight through is: 1.06 x 10 4 J of kinetic energy 1.90 x 106 N/C 1.06 x 10 4 J of electric potential energy 1.06 x 107 N/C 6.06 x 106 N/C 3.10 x 108 N/C 22. A 15 cm metal rod, with a mass of 50 g, lies perpendicular to an external magnetic field of 0.50 T. The current necessary to counteract the gravitational force on the rod is: 0.065 A 6.5 A 65 A 0.65 A 21. A battery delivers a current of 50 mA to an electronic device for 120 seconds. The number of electrons that flow through the electronic device is a.b x 10cd. The values for a, b, c, and d are (Record your four digit answer) (Record your answer in the numerical-response section below.) Your answer: 90

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