Question: Use the following information to compress one time unit per move using the least-cost method. Reduce the schedule until you reach the crash point of
Use the following information to compress one time unit per move using the least-cost method. Reduce the schedule until you reach the crash point of the network.
| Activity | Crash cost | Maximum | ||
| ID | (Slope) | Crash Time | Normal time | Normal cost |
| A | 0 | 0 | 3 | 150 |
| B | 100 | 1 | 4 | 200 |
| C | 60 | 1 | 3 | 250 |
| D | 40 | 1 | 4 | 200 |
| E | 0 | 0 | 2 | 250 |
| F | 30 | 2 | 3 | 200 |
| G | 20 | 1 | 2 | 250 |
| H | 60 | 2 | 4 | 300 |
| I | 200 | 1 | 2 | 200 |
| Total direct normal costs | $2,000 | |||
The indirect costs for each duration are $1,500 for 17 weeks, $1,450 for 16 weeks, $1,400 for 15 weeks, $1,350 for 14 weeks, $1,300 for 13 weeks, $1,250 for 12 weeks, $1,200 for 11 weeks, and $1,150 for 10 weeks. For each move identify what activity or activities were crashed and the adjusted total cost, making the most appropriate choice among activities that cost the same. To compress from time period 17 to time 16, crash the following activity(s):
check all that apply 1
- A
- B
- C
- D
- E
- F
- G
- H
- I
What is the adjusted total cost at time period 16?
To compress from time period 16 to time 15, crash the following activity(s):
check all that apply 2
- A
- B
- C
- D
- E
- F
- G
- H
- I
What is the adjusted total cost at time period 15?
To compress from time period 15 to time 14, crash the following activity(s):
check all that apply 3
- A
- B
- C
- D
- E
- F
- G
- H
- I
What is the adjusted total cost at time period 14?
What is the crash point of the network? (Hint: To obtain crash point, crash the project as much as is possible.)
| Time period | Weeks | |
| Total cost |
What is the optimum cost-time schedule for the project? ______weeks
What is this cost? _________
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