Use the graph and data table below to determine: stress (psi) strain(in/in) 0 0 4,100 0.00025...

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Use the graph and data table below to determine: stress (psi) strain(in/in) 0 0 4,100 0.00025 7,850 0.0005 11,450 0.00075 15,000 0.00096 17,350 19,800 21,300 19,920 27,260 31,140 26,430 0.001117 0.00143 0.001875 0.0025 0.00312 0.0042 0.00472 Stress (psi) 35,000 c) Ultimate strength (units: psi) 30,000 d) Rupture strength (units: psi) 25,000 20,000 15,000 10,000 3,000 b) Modulus of elasticity (units: ksi) a) Proportional limits: (stress in units of psi, strain in units of in/in) Stress Strain Curve O 0 0.0005 0.001 0.0005 0.002 0.0025 0.003 0.0035 0.004 0.0045 0.005 Strain (in/in) A 100 ft. long surveyor's steel tape with a cross sectional area of 0.004 square inches must be stretched with a pull of 19 lb. when in use. Assume E = 28,000 ksi. Compute the total elongation in the 100 ft. tape (units: in). Use the graph and data table below to determine: stress (psi) strain(in/in) 0 0 4,100 0.00025 7,850 0.0005 11,450 0.00075 15,000 0.00096 17,350 19,800 21,300 19,920 27,260 31,140 26,430 0.001117 0.00143 0.001875 0.0025 0.00312 0.0042 0.00472 Stress (psi) 35,000 c) Ultimate strength (units: psi) 30,000 d) Rupture strength (units: psi) 25,000 20,000 15,000 10,000 3,000 b) Modulus of elasticity (units: ksi) a) Proportional limits: (stress in units of psi, strain in units of in/in) Stress Strain Curve O 0 0.0005 0.001 0.0005 0.002 0.0025 0.003 0.0035 0.004 0.0045 0.005 Strain (in/in) A 100 ft. long surveyor's steel tape with a cross sectional area of 0.004 square inches must be stretched with a pull of 19 lb. when in use. Assume E = 28,000 ksi. Compute the total elongation in the 100 ft. tape (units: in).

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a Proportional limits stress in units of psi strain in units of inin The proportional limit is defin... View the full answer