Use the graph to find the limit L (if it exists). If the limit does not existI explain why. (If an answer does not exist, enter DNE_) 900 = X i i . . . ix 4 5 8 101214- The limit does not exist at x = 2 because 112) t 2. The limit does not exist at x = 2 because the function increases and decreases without bound as x approaches 2. The limit does not exist at x : 2 because the function does not approach f0.) as x approaches 2. The limit does not exist at x = 2 because the function is hot continuous at any x value. TH:- Iimii- avian: :I' v 7 1 (a) lim g(x) x - 2 L = O The limit does not exist at x = 2 because f(2) # 2. The limit does not exist at x = 2 because the function increases and decreases without bound as x approaches 2. O The limit does not exist at x = 2 because the function does not approach f(2) as x approaches 2. O The limit does not exist at x = 2 because the function is not continuous at any x value. O The limit exists at x = 2. (b) lim g(x) x-0 L = O The limit does not exist at x = 0 because the function does not approach f(0) as x approaches 0. O The limit does not exist at x = 0 because f(0) # 0. The limit does not exist at x = 0 because the function is not continuous at any x value. The limit does not exist at x = 0 because the function increases and decreases without bound as x approaches 0. The limit exists at x = 0.Find the open intervals on which the function is increasing or decreasing. (Enter your answers using interval notation. If an answer does not exist, enter DNE.) for) = (x - 112w 11) increasing I X Find the point of inflection of the graph of the function. (If an answer does not exist, enter DNE.) f(x) = x3 - 15x2 (x, y) = X