Question: Use the hash function h(x) = x mod 11 to load the following values 28, 84, 17, 39, 50 using the following c(i) = (+/-)

Use the hash function h(x) = x mod 11 to load the following values 28, 84, 17, 39, 50 using the following c(i) = (+/-) 2 to resolve collisions. After loading the table (table index starts at 0): The table's index that has the value 50 is and the table's index that has the value 39 is
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