Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval.

$e^x=4-3x,(0,1)$

The equation $e^x=4-3x$ is equivalent to the equation $f(x)=e^x-4+3x=0.f(x)$ is continuous on the interval $0,1,$

$f(0)=$ Your answer cannot be understood or graded. More Information, and $f(1)=$ Your answer cannot be understood or graded. More Information. Since there is a number $c$ in $(0,1)$ such that $f(c)=0$ by the Intermediate Value Theorem. Thus, there is a root of the equation $e^x=4-3x,$ in the interval $(0,1).$