Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval.

$x^{4}x-3=0,(1,2)$

$f(x)=x^{4}x-3$ is $$ on the closed interval $[1,2],f(1)=,$ and $f(2)=.$ Since there is a number $c$ in $(1,2)$ such that $f(c)=$ by the Internediate Value Theorem. Thus, there is a $$ Selectlof the equation $x^{4}x-3=0$ in the interval $(1,2).$