Question: use the proof checker below to prove that the given argument is valid according to the constructive dilemma rule. The given numbered lines are the

 use the proof checker below to prove that the given argumentis valid according to the constructive dilemma rule. The given numbered linesare the argument's premises, and the line beginning with a single slashis the argument's conclusion. The proof can be completed in one additionalline. Click Add Line, and enter the line that follows according toconstructive dilemma. Since constructive dilemma requires two premises, cite the two lines

use the proof checker below to prove that the given argument is valid according to the constructive dilemma rule. The given numbered lines are the argument's premises, and the line beginning with a single slash is the argument's conclusion. The proof can be completed in one additional line. Click Add Line, and enter the line that follows according to constructive dilemma. Since constructive dilemma requires two premises, cite the two lines from which the new line follows and also cite the rule used (constructive dilemma in this case). Note: The last line of a proof must always match the conclusion line. When you have completed the proof, click check Proof. 2 (YVo) (ZvJ) EVX 5 v Check Add Line X Delete Line V Check Proof use the proof checker below to prove that the given argument is valid according to the constructive dilemma rule. The given numbered lines are the argument's premises, and the line beginning with a single slash is the argument's conclusion. The proof can be completed in one additional line. Click Add Line, and enter the line that follows according to constructive dilemma. Since constructive dilemma requires two premises, cite the two lines from which the new line follows and also cite the rule used (constructive dilemma in this case). Note: The last line of a proof must always match the conclusion line. When you have completed the proof, click check Proof. 2 (YVo) (ZvJ) EVX 5 v Check Add Line X Delete Line V Check Proof

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