Use the result $\underset{0}{lim}\frac{sin}{}=1$ to evaluate the following limit: $\underset{0}{lim}\frac{tan(2)}{5}.$

$($a$)\frac{2}{5}$

$($b$)\frac{5}{2}$

$($c$)0$

$($d$)1$

$($e$)$ None of the above.