Use the RSA cipher with public key (pq, e) = (23 . 31, 43) = (713, 43) and private key (pq, d), where d = 307, to decrypt the given ciphertext and find the original message. (Assume the letters of the alphabet are encoded as follows: A = 01, B = 02, C = 03, . . ., Z = 26.) 048 018 128 Since d = 307 = 256 + 32 + 16 + 2 + 1, find the first letter of the decrypted message by computing 048 mod 713. Now 0481 = a (mod 713) 0482 = b (mod 713) 0484 = c (mod 713) 0488 = d (mod 713) 04816 = e (mod 713) 04832 =f (mod 713) 04864 = g (mod 713) 048128 = h (mod 713) 048256 = / (mod 713). The result is that a = b = , C= , d = g = , h = and i = Enter an exact number. Thus, 04830 mod 713 = (a . b . e . f . i) mod 713 = , and so the first letter in the encrypted message is Repeat these computations for each encrypted letter and find the completed decrypted message. Need Help? Read It Submit