Question: Use the secant method on the circle function (x+1)^2 + (y-2)^2 = 16 to find a positive real root. Set your initial guess to xi

Use the secant method on the circle function (x+1)^2 +

(y-2)^2 = 16 to find a positive real root. Set your initial guess to

xi = 3 and xi-1 = 0.5. Approach the solution from the first and

fourth quadrants. When solving for f(x) in the fourth quadrant, be

sure to take the negative value of the square root. Why does your

solution diverge?

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