Use the substitution $t=ln(x)yp$ for $\frac{dy}{dt}$ and $ypp$ for $\frac{d^{2}y}{d{t}^2}.x^2{y}^{\text{'}\text{'}}-11x{y}^{\text{'}}+36y=0$

Solve the original equation $by$ solving the new equation using the procedures $in$ Sections $4\mathrm{.}3-4\mathrm{.}5.$

$y(x)=$

$,x>0$