Use the table below to estimate ${\displaystyle \underset{1}{\overset{2}{}}}g(t)dt$ by MID$(5).$

MID$(5)=$

$$

$\backslash$table$[[t,1\mathrm{.}0,1\mathrm{.}1,1\mathrm{.}2,1\mathrm{.}3,1\mathrm{.}4,1\mathrm{.}5,1\mathrm{.}6,1\mathrm{.}7,1\mathrm{.}8,1\mathrm{.}9,2\mathrm{.}0],[g(t),-2\mathrm{.}1,-1\mathrm{.}8,-1\mathrm{.}4,-0\mathrm{.}8,-1\mathrm{.}4,-1\mathrm{.}5,-1\mathrm{.}9,-2,-0\mathrm{.}6,0\mathrm{.}5,1\mathrm{.}3]]$